Otherwise... You can try cSplit library(splitstackshape) setnames(cSplit(mergedDf, 'PROD_CODE', ','), paste0('X',1:4))[] # X1 X2 X3 X4 #1: PRD0900033 PRD0900135 PRD0900220 PRD0900709 #2: PRD0900097 PRD0900550 NA NA #3: PRD0900121 NA NA NA #4: PRD0900353 NA NA NA #5: PRD0900547 PRD0900614 NA NA Or using the devel version of data.table i.e. This should get you headed in the right direction, but be sure to check out the examples pointed out by @Jaap in the comments. A vector is often written in bold, like a or b so we know it is not a scalar:. Since all single annotations have same height, the value of simple_anno_size is a single unit value. Groups are defined by the structure of the tree above the cut. You can alternatively look at the 'Large memory and out-of-memory data' section of the High Perfomance Computing task view in R. Packages designed for out-of-memory processes such as ff may help you. The norm of a vector is its length, and the length of a vector must always be positive (or zero). Dear all, I have a matrix M (lot of lines, 7 columns) and a vector v (again lot of lines but not the same ad M and 3 columns) and I need to find the lines of M for which the first 3 columns are equal to the column of a certain line of v. height: either a vector or matrix of values describing the bars which make up the plot. Try.. zz <- lapply(z,copy) zz[[1]][ , newColumn := 1 ] Using your original code, you will see that applying copy() to the list does not make a copy of the original data.table. In your case, you're getting the values 2 and 4 and then trying to index your vector again using its own values. Height is a scalar when defining a constant value, i.e. You can do myStr <- "0.76+0.41j" myStr_complex <- as.complex(sub("j","i",myStr)) Im(myStr_complex) # [1] 0.41 ... You can try library(data.table)#v1.9.4+ setDT(yourdf)[, .N, by = A] ... You can do it with rJava package. If FALSE, the columns of height are portrayed as stacked bars, and if TRUE … multivariate multiple regression can be done by lm(). In your case, you have a data.frame with heights in the second column, and names in the first, so you want to do: You can do something like this: print_test<-function(x) { Sys.sleep(x) cat("hello world") } print_test(15) If you want to execute it for a certain amount of iterations use to incorporate a 'for loop' in your function with the number of iterations.... You can create a similar plot in ggplot, but you will need to do some reshaping of the data first. Velocity is speed with a direction. Count number of rows meeting criteria in another table - R PRogramming, Twitter: Get followers from multiple users at once, Store every value in a sequence except some values, Highlighting specific ranges on a Graph in R, ggplot2 & facet_wrap - eliminate vertical distance between facets, how to get values from selectInput with shiny, Limit the color variation in R using scale_color_grey, Appending a data frame with for if and else statements or how do put print in dataframe, Replace -inf, NaN and NA values with zero in a dataset in R, Subtract time in r, forcing unit of results to minutes [duplicate], How to set x-axis with decreasing power values in equal sizes. \begin{cases} x1 &= .5x4\\ x2 &= x4\\ x3 &= .5x4\\ x4 & \text{is free}\\ \end{cases} Here is the matrix I pulling the information from just in case you need it. Scalar and Vector Attributes. hist(x) creates a histogram bar chart of the elements in vector x.The elements in x are sorted into 10 equally spaced bins along the x-axis between the minimum and maximum values of x. hist displays bins as rectangles, such that the height of each rectangle indicates the number of elements in the bin.. Speed vs Velocity. The angles must be a column vector (i.e., numpy array). Here is some sample code based on what you had in your original problem which will aggregate Twitter results for a set of users: # create a data frame with 4 columns and no rows initially df_result <- data.frame(t(rep(NA, 4))) names(df_result) <- c('id', 'name', 's_name', 'fol_count') df_result <- df_result[0:0,] #... if (length(z) %% 2) { z[-c(1, ceiling(length(z)/2), length(z))] } else z[-c(1, c(1,0) + floor(length(z)/2), length(z))] ... Or you could place a rectangle on the region of interest: rect(xleft=1994,xright = 1998,ybottom=range(CVD$cvd)[1],ytop=range(CVD$cvd)[2], density=10, col = "blue") ... Change the panel.margin argument to panel.margin = unit(c(-0.5,0-0.5,0), "lines"). Fixed my typo in the first matrix. This is only useful when height is a matrix. I think this code should produce the plot you want. library(ggmap) map <- get_map(location = "Mumbai", zoom = 12) df <- data.frame(location = c("Airoli", "Andheri East", "Andheri West", "Arya Nagar", "Asalfa", "Bandra East", "Bandra West"), values... sapply iterates through the supplied vector or list and supplies each member in turn to the function. n=length(y) model_a1 <- auto.arima(y) plot(x=1:n,y,xaxt="n",xlab="") axis(1,at=seq(1,n,length.out=20),labels=index(y)[seq(1,n,length.out=20)], las=2,cex.axis=.5) lines(fitted(model_a1), col = 2) The result depending on your data will be something similar: ... You are just saving a map into variable and not displaying it. R cannot tell which variable is which when you pass it an entire data.frame to plot. However, if an object travelled a certain height, such as a tossed baseball, then it would be considered a vector. I am getting the error "Height must be a vector of Matrix." If you read on the R help page for as.Date by typing ?as.Date you will see there is a default format assumed if you do not specify. It looks like you're trying to grab summary functions from each entry in a list, ignoring the elements set to -999. R cannot tell which variable is which when you pass it an entire data.frame to plot. This should only take a vector or a matrix. The best selection of Royalty Free Height Vector Art, Graphics and Stock Illustrations. For a barplot, using ?barplot will tell you what is needed: barplot(height, width = 1, space = … The pts must be a two-column numpy array of x,y positions (angle transforms currently only work in 2D). If height is a matrix and beside is FALSE then each bar of the plot corresponds to a column of height, with the values in the column giving the heights of stacked sub-bars'' making up the bar. ## Create input input <- names<-(lapply(landelist, function(x) sample(0:1, 1)), landelist) filterland <- c() for (landeselect in landelist) if (input[[landeselect]] == TRUE) # use [[... some reproducible code would allow me to give you some example code, but in the absence of that... wrap what you currently have in another if(), checking for length = 0 (or just && it, with the NULL check first), and display your favorite placeholder message.... A better approach would be to read the files into a list of data.frames, instead of one data.frame object per file. R — frequencies within a variable for repeating values, how to call Java method which returns any List from R Language? A.2 MATRICES We can now extend these ideas to any rectangular array of numbers, which we call a matrix… If h is a vector of numbers, the output will be a matrix with a column for each value in h. The default is NULL. The following is an example of a matrix with 2 rows and 3 columns. Your sapply call is applying fun across all values of x, when you really want it to be applying across all values of i. The problem is that you pass the condition as a string and not as a real condition, so R can't evaluate it when you want it to. sz = size(A) returns a row vector whose elements are the lengths of the corresponding dimensions of A.For example, if A is a 3-by-4 matrix, then size(A) returns the vector [3 4].. R: Using the “names” function on a dataset created within a loop, How to quickly read a large txt data file (5GB) into R(RStudio) (Centrino 2 P8600, 4Gb RAM), Rbind in variable row size not giving NA's, Subsetting rows by passing an argument to a function. Essentially, the matrix is represented by a Cartesian coordinate system, in which the rows of the matrix are parallel to the x-axis and the columns to the y-axis of … To get the sapply to do what I assume you want to do, you can do the following: sapply(X = 1:length(x), FUN = fun, x =... You can put your records into a data.frame and then split by the cateogies and then run the correlation for each of the categories. The height of the simple annotation is controlled by simple_anno_size argument. Speed is how fast something moves. Lia = ismember(A,B,'rows') treats each row of A and each row of B as single entities and returns a column vector containing logical 1 (true) where the rows of A are also rows of B.Elsewhere, the array contains logical 0 (false).. The operation can then be applied to the matrix. so c is a vector, it has magnitude and direction Your intuition is correct. Download 9,500+ Royalty Free Height Vector Images. A vector is a series of numbers, like a matrix with one column but multiple rows, that can often be represented spatially. You can vote up the ones you like or vote down the ones you don't like, and go to the original project or source file by following the links above each example. So, in some sense what we say is that these 2 vectors(v1 and v2) characterize the space or they form a basis for space and any vector in this space, can simply be written as a linear combination of these 2 vectors.Now you can notice, the linear combinations are actually the numbers themselves. Matrix. From Hadley's Advanced R, "x$y is equivalent to x[["y", exact = FALSE]]." I think you want to minimize the square of a-fptotal ... ff <- function(x) myfun(x)^2 > optimize(ff,lower=0,upper=30000)$minimum [1] 28356.39 $objective [1] 1.323489e-23 Or find the root (i.e. It is possible to add both scalar and vector attributes to datasets. You are using it to copy a list. It's easier to think of it in terms of the two exposures that aren't used, rather than the five that are. This is my first general solution and I want to put it in vector form. In linux, you could use awk with fread or it can be piped with read.table. It's generally not a good idea to try to add rows one-at-a-time to a data.frame. Putting feature vectors for objects together can make up a feature space.. Scalar For single matrix input, C has size [size(A,2) size(A,2)] based on the number of random variables (columns) represented by A.The variances of the columns are along the diagonal. This should only take a vector or a matrix. You can try something like this: barplot(as.matrix(data), beside=T , legend.text=T, col=c("red" , "green", "blue"), ylim=c(0,140), ylab="height") Hopefully this helps you out. Pastebin.com is the number one paste tool since 2002. height: You can specify either a Vector or a Matrix of values. If it is a Vector, the R bar chart created with a sequence of rectangular bars, and each bar height depends upon the vector value. This array must have the same number of rows as angles. how to read a string as a complex number? it's better to generate all the column data at once and then throw it into a data.frame. Notation. A matrix is a collection of data elements arranged in a two-dimensional rectangular layout. Also, thanks to akrun for the test data. Instead, the dot operator must be used to get the desired data into a matrix. collapse is the Stata equivalent of R's aggregate function, which produces a new dataset from an input dataset by applying an aggregating function (or multiple aggregating functions, one per variable) to every variable in a dataset. For some reason the top and bottom margins need to be negative to line up perfectly. 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